Which one of the following combinations of the concentration of urea (in both mg/dL and mmol/L) is equivalent to a serum blood urea nitrogen (BUN) concentration of 15 mg/dL?
• Atomic weights: N = 14, C = 12, O = 16, H = 1.
The molecular weight of urea is 60. Urea contains 2 nitrogen atoms, with a combined molecular weight of 28. To convert from urea nitrogen in mg/dL to urea in mg/dL, divide 60 by 28 to obtain a factor of 2.14; therefore, 2.14 g of urea is equivalent to 1.0 g of urea nitrogen.
If the urea nitrogen value of 15 mg/dL is multiplied by 2.14, one obtains a concentration of urea of 32 mg/dL. To convert the urea concentration of 32 mg/dL into mmol/L, one multiplies 32 by 10, and then divides by the molecular weight of urea (i.e., 60) to obtain 5.3 mmol/L.
The molecular weight of urea is 60. Urea contains 2 nitrogen atoms, with a combined molecular weight of 28. To convert from urea nitrogen in mg/dL to urea in mg/dL, divide 60 by 28 to obtain a factor of 2.14; therefore, 2.14 g of urea is equivalent to 1.0 g of urea nitrogen.
If the urea nitrogen value of 15 mg/dL is multiplied by 2.14, one obtains a concentration of urea of 32 mg/dL. To convert the urea concentration of 32 mg/dL into mmol/L, one multiplies 32 by 10, and then divides by the molecular weight of urea (i.e., 60) to obtain 5.3 mmol/L.
The molecular weight of urea is 60. Urea contains 2 nitrogen atoms, with a combined molecular weight of 28. To convert from urea nitrogen in mg/dL to urea in mg/dL, divide 60 by 28 to obtain a factor of 2.14; therefore, 2.14 g of urea is equivalent to 1.0 g of urea nitrogen.
If the urea nitrogen value of 15 mg/dL is multiplied by 2.14, one obtains a concentration of urea of 32 mg/dL. To convert the urea concentration of 32 mg/dL into mmol/L, one multiplies 32 by 10, and then divides by the molecular weight of urea (i.e., 60) to obtain 5.3 mmol/L.
The molecular weight of urea is 60. Urea contains 2 nitrogen atoms, with a combined molecular weight of 28. To convert from urea nitrogen in mg/dL to urea in mg/dL, divide 60 by 28 to obtain a factor of 2.14; therefore, 2.14 g of urea is equivalent to 1.0 g of urea nitrogen.
If the urea nitrogen value of 15 mg/dL is multiplied by 2.14, one obtains a concentration of urea of 32 mg/dL. To convert the urea concentration of 32 mg/dL into mmol/L, one multiplies 32 by 10, and then divides by the molecular weight of urea (i.e., 60) to obtain 5.3 mmol/L.
The molecular weight of urea is 60. Urea contains 2 nitrogen atoms, with a combined molecular weight of 28. To convert from urea nitrogen in mg/dL to urea in mg/dL, divide 60 by 28 to obtain a factor of 2.14; therefore, 2.14 g of urea is equivalent to 1.0 g of urea nitrogen.
If the urea nitrogen value of 15 mg/dL is multiplied by 2.14, one obtains a concentration of urea of 32 mg/dL. To convert the urea concentration of 32 mg/dL into mmol/L, one multiplies 32 by 10, and then divides by the molecular weight of urea (i.e., 60) to obtain 5.3 mmol/L.